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WAEC - Physics (1994 - No. 18)

A battery of e.m.f 10V an internal resistance 2Ω is connected to a resistance of 6Ω. Calculate the p.d
8.75V
7.50V
5V
2.50V
1.25V

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V = E - Ir = 10V - \(\frac{10 \times 2}{8}\) = 7.5V

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