WAEC - Mathematics (1991 - No. 29)
In the diagram above, ATR is a tangent at the point T to the circle center O, if ∠TOB = 145°, find ∠TAO
20o
35o
45o
55o
65o
Forklaring
From the figure, < ATO = 90°
< AOT = 180° - 145° = 35°
\(\therefore\) < TAO = 180° - (90° + 35°)
= 55° (sum of angle in a triangle)