WAEC - Further Mathematics (2006 - No. 20)
Simplify \(8^{n} \times 2^{2n} \div 4^{3n}\)
\(2^{-n}\)
\(2^{1 - n}\)
\(2^{n}\)
\(2^{n + 1}\)
Forklaring
\(8^{n} \times 2^{2n} \div 4^{3n} = 2^{3n} \times 2^{2n} \div 2^{6n}\)
\(2^{2n + 3n - 6n}\)
= \(2^{-n}\)