WAEC - Chemistry (2001 - No. 19)
What is the oxidation number of nitrogen in Al(NO\(_3\))\(_3\)?
+ 1
+ 3
+ 5
+ 6
Forklaring
The oxidation number of Al = +3 , O = - 2, N =? in Al(NO\(_3\) )\(_3\)
Al(NO\(_3\) )\(_3\) = 0
Al + 3N + 3(O3) = 0
+3 + 3N + 3(-2 X 3) = 0
3N = 18 - 3
N = 15/3
N = + 5 - Option C