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JEE Advance - Mathematics (2007 - No. 22)
The sum $${V_1}$$+$${V_2}$$ +...+$${V_n}$$ is
$${1 \over {12}}n(n + 1)\,(3{n^2} - n + 1)$$
$${1 \over {12}}n(n + 1)\,(3{n^2} + n + 2)$$
$${1 \over 2}n(2{n^2} - n + 1)$$
$${1 \over 3}(2{n^3} - 2n + 3)$$
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