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JEE Advance - Mathematics (1998 - No. 47)
If $$P=(x, y)$$, $${F_1} = \left( {3,0} \right),\,{F_2} = \left( { - 3,0} \right)$$ and $$16{x^2} + 25{y^2} = 400,$$ then $$P{F_1} + P{F_2}$$ equals
$$8$$
$$6$$
$$10$$
$$12$$
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