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JAMB - Mathematics (2020 - No. 11)

If log\(_{10}\)2 = 0.3010 and log\(_{10}\)3 = 0.4771, eventually without using the logarithm tables, log\(_{10}\)4.5
0.3010
0.4771
0.6532
0.9542

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log\(_{10}\)2 = 0.3010 and log\(_{10}\)3 = 04771

log\(_{10} 4.5 = log_{10}\) (\(\frac{3 \times 3}{2}\))

log\(_{10}\) 3 + log\(_{10}\) 3 - log\(_{10}\)2 = 0.4471 + 0.771 - 0.3010

= 0.6532

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