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JAMB - Mathematics (2011 - No. 6)

If log318 + log33 - log3x = 3, Find x.
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log\(_{3}^{18}\) + log\(_{3}^{3}\) - log\(_{3}^{x}\) = 3

log\(_{3}^{18}\) + log\(_{3}^{3}\) - log\(_{3}^{x}\) = 3log33

log\(_{3}^{18}\) + log\(_{3}^{3}\) - log\(_{3}^{x}\) = log333

log3(\(\frac{18 \times 3}{X}\)) = log333

\(\frac{18 \times 3}{X}\) = 33

18 x 3 = 27 x X

x = \(\frac{18 \times 3}{27}\)

= 2

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