JAMB - Mathematics (1991 - No. 36)
From a point Z, 60 m north of X, a man walks 60√3m eastwards to another point Y. Find the bearing of Y from X.
0.30o
045o
060o
090o
Forklaring
tan \(\theta\) = \(\frac{60\sqrt{3}}{60}\) = \(\sqrt{3}\)
\(\theta\) = tan \(\frac{1}{3}\) = 60o
Bearing of y from x = 060o
\(\theta\) = tan \(\frac{1}{3}\) = 60o
Bearing of y from x = 060o