JAMB - Mathematics (1979 - No. 35)
What is log\(_7{(49^a)}\) - log\(_{10}^{(0.01)}\)?
\(\frac{49^a}{100}\)
\(\frac{a}{2}\) + 2
72a + 2
2a + 2
\(\frac{2a}{2}\)
Forklaring
log7(49a) - log10(0.01) = log7(72)a - log10100
log772a - log101 - log10 102
= 2a - 2
= 2a + a
log772a - log101 - log10 102
= 2a - 2
= 2a + a