JAMB - Biology (2003 - No. 38)
A man and his wife are both heterozyous for the sickle-cell trait. The likely percentage of their offspring that will be either carriers or sicklers is
75%
50%
25%
100%
Forklaring
An heterozygote for sickle-cell anaemia = AS
Crossing two AS persons, we have one AA, two AS and one SS.
\(\therefore\) The probability that the children are either carriers or sicklers = \(\frac{3}{4}\)
= 75%