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WAEC - Mathematics (2010 - No. 39)

In the diagram, QR//ST, /PQ/ = /PR/ and < PST = 75o. Find the value of y
105o
110o
130o
150o

Vysvětlení

In \(\bigtriangleup\) PQR,

Q = S = 75o (Corresponding angle)

R = Q = 75o (Base angles of an isosceles \(\bigtriangleup\))

But, y + 75o = 180o (Sum of angles in a straight line)

y = 180 - 75

y = 105o

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