JEE Advance - Mathematics (1978 - No. 17) | ExamPlay

JEE Advance - Mathematics (1978 - No. 17)

Solve for $$x:{4^x} - {3^{^{x - {1 \over 2}}}}\, = {3^{^{x + {1 \over 2}}}}\, - {2^{2x - 1}}$$

0

1

3/2

2

5/2

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