JEE MAIN - Chemistry (2009 - No. 25)
Calculate the wavelength (in nanometer) associated with a proton moving at 1.0 x 103 ms−1
(Mass of proton = 1.67 $$\times$$ 10-27 kg and h = 6.63 $$\times$$ 10-34 Js) :
0.40 nm
2.5 nm
14.0 nm
0.32 nm
Vysvětlení
Wavelength$$\left( \lambda \right)$$ = $${h \over {mv}}$$
= $${{6.63 \times {{10}^{ - 34}}} \over {1.67 \times {{10}^{ - 27}} \times {{10}^3}}}$$
= 0.4 $$\times$$ 10-9
= 0.4 nm
= $${{6.63 \times {{10}^{ - 34}}} \over {1.67 \times {{10}^{ - 27}} \times {{10}^3}}}$$
= 0.4 $$\times$$ 10-9
= 0.4 nm