JAMB - Physics (2010 - No. 16)
The pressure of one mole of an ideal gas of volume 10-2 m3 at a temperature of 27°c is
[molar gas constant = 8.3 J mol-1 k-1]
[molar gas constant = 8.3 J mol-1 k-1]
2.49 x 104 Nm-2
2.24 x 104 Nm-2
2.49 x 105 Nm-2
2.24 x 105 Nm-1
Vysvětlení
T = 27 + 273 = 300 K, volume, V = 10-2 m3 molar gass constant, R = 8.3 Jmol- 1k - 1 number of mole, n = 1
PV = NRT
i.e P = (NRT)/V = (1 x 8.3 x 300)/10-2
= 2.49 x 10\(^5\) Nm\(^-2\)
PV = NRT
i.e P = (NRT)/V = (1 x 8.3 x 300)/10-2
= 2.49 x 10\(^5\) Nm\(^-2\)