ExamPlay Light Logo
Přihlaste se

JAMB - Physics (1986 - No. 26)

A wave of frequency 10Hz forms a stationary wave pattern in a medium where the velocity is 20cms-1. The distance between adjacent nodes is
1.0cm
1.5cm
2.0cm
5.0cm

Vysvětlení

\(\lambda\) = \(\frac{v}{f}\)

= \(\frac{20}{10}\)

= 2cm ; distance between adjacent nodes 

= 2cm \ 2 

= 1cm

Komentáře (0)

Přihlaste se pro komentář
Inzerát
BrainBehindX Inc Logo
©2026; Powered By BrainBehindX Inc