∫\(\frac{5}{x}\) dx = 5 ∫\(\frac{1}{x}\) = 5Inx

  Since the integral of \(\frac{1}{x}\) is Inx

  ∫\(^2\) \(_1\)∫ \(\frac{5}{x}\) dx = 5

  dx = 5 (In<2 – InIn1)

  = 3.4657

  = 3.47