WAEC - Physics (2000 - No. 30)
A turning fork of frequency 600Hz is sounded over a closed resonance tube. If the first and second resonant positions are 0.130m and 0.413m respectively, calculate the speed of sound in air
508.4ms-1
480.0ms-1
339.6ms-1
169.8ms-1
Explicació
\(v = f\lambda\)
\(v = 2f \times (l_{2} - l_{1})\)
\(v = 2 \times 600 \times(0.413 - 0.130)\)
\(v = 1200 \times 0.283\)
\(v = 339.6ms^{-1}\)