16\(^{\frac{5}{4}}\) x 2\(^{-3}\) x 3\(^0\)

= \((2^4)^{\frac{5}{4}} \times 2^{-3} \times 1\)

= \(2^5 \times 2^{-3} \times 1\)

= \(2^2\)

= 4.