WAEC - Further Mathematics (2021 - No. 9)
If α and β are the roots of 3x\(^2\) - 7x + 6 = 0, find \(\frac{1}{α}\) + \(\frac{1}{β}\)
\(\frac{7}{6}\)
\(\frac{7}{3}\)
\(\frac{14}{5}\)
\(\frac{14}{3}\)
Explicació
3x\(^2\) - 7x + 6 = 0
α + β = \(\frac{7}{3}\);
αβ = 2;
\(\frac{1}{α}\) + \(\frac{1}{β}\) = \(\frac{α +β}{αβ}\)
\(\frac{7}{3}\) ÷ 2
= \(\frac{7}{6}\)