JEE Advance - Mathematics (1996 - No. 20)
A rectangle $$PQRS$$ has its side $$PQ$$ parallel to the line $$y = mx$$ and vertices $$P, Q$$ and $$S$$ on the lines $$y = a, x = b$$ and $$x = -b,$$ respectively. Find the locus of the vertex $$R$$.
x(m^2 - 1) - ym + (m^2 + 1)b + am = 0
x(m^2 + 1) - ym + (m^2 - 1)b + am = 0
x(m^2 - 1) + ym + (m^2 + 1)b - am = 0
x(m^2 - 1) - ym - (m^2 + 1)b + am = 0
x(m^2 - 1) - ym + (m^2 - 1)b + am = 0