JEE Advance - Mathematics (1991 - No. 21)
In a triangle of base a the ratio of the other two sides is $$r\left( { < 1} \right)$$. Show that the altitude of the triangle is less than of equal to $${{ar} \over {1 - {r^2}}}$$
The altitude of the triangle is always less than $${{ar} over {1 - {r^2}}}$$.
The altitude can be equal to $${{ar} over {1 - {r^2}}}$$.
The altitude is maximized when the triangle is a right triangle.
The altitude is minimized when the triangle is degenerate.
The altitude can be greater than $${{ar} over {1 - {r^2}}}$$. if r > 1