JAMB - Mathematics (2023 - No. 20)
A boat sails 8 km north from P to Q and then sails 6 km west from Q to R. Calculate the bearing of R from P. Give your answer to the nearest degree.
217\(^o\)
323\(^o\)
037\(^o\)
053\(^o\)
Explicació
tan θ = \(\frac {opp}{adj} = \frac {RQ}{QP} = \frac {6}{8}\)
tan θ = 0.75
θ = tan\(^{-1} (0.75) = 36.87^o\)
∴ The bearing of R from P = 360\(^o\) - 36.87\(^o\) = 323\(^o\) (to the nearest degree)