JAMB - Mathematics (2011 - No. 38)
\(\begin{array}{c|c} No & 0 & 1 & 2 & 3 & 4 & 5 \\ \hline Frequency & 1 & 4 & 3 & 8 & 2 & 5 \end{array}\). From the table above, find the median and range of the data respectively.
(8,5)
(3, 5)
(5 , 8)
(5 , 3)
Explicació
Median = \(\sum f\) = 23+1 = 24Th = \(\frac{24}{2}\) = 12TH position is 8 = 3
Range = 5 - 0 = 5
(3, 5)
Range = 5 - 0 = 5
(3, 5)