JAMB - Mathematics (2004 - No. 31)
Factorize completely ac - 2bc - a\(^2\) + 4b\(^2\)
(a - 2b)(c - a - 2b)
(a - 2b)(c + a +2b)
(a - 2b)(c - a + 2b)
(a - 2b)(c + a - 2b)
Explicació
ac - 2bc - a\(^2\) + 4b\(^2\)
ac - 2bc - (a\(^2\) - 4b\(^2\))
ac - 2bc - (a\(^2\) -(2b)\(^2\))
c(a - 2b) - {(a - 2b)(a + 2b)}
(a - 2b)(c - (a + 2b))
(a - 2b)(c - a - 2b)
ac - 2bc - (a\(^2\) - 4b\(^2\))
ac - 2bc - (a\(^2\) -(2b)\(^2\))
c(a - 2b) - {(a - 2b)(a + 2b)}
(a - 2b)(c - (a + 2b))
(a - 2b)(c - a - 2b)