JAMB - Mathematics (1995 - No. 14)
Factorize completely the expression \(abx^2 + 6y - 3ax - 2byx\)
(ax - 2y)(bx - 3)
(bx + 3)(2y - ax)
(bx + 3)(ax - 2y)
(ax - 2y)(ax - b)
Explicació
\(abx^{2} + 6y - 3ax - 2byx\)
Collecting like terms, we have
\(abx^{2} - 3ax + 6y - 2byx\)
= \(ax(bx - 3) + 2y(3 - bx)\)
= \(ax(bx - 3) - 2y(bx - 3)\)
= \((ax - 2y)(bx - 3)\)