WAEC - Physics (2014 - No. 23)
A car traveling at 30ms\(^{-1}\) overcomes a frictional resistance of 100N while moving. Calculate the power developed by the engine. [1 hp = 0.75 kW]
0.23hp
0.40hp
4.00hp
4.40hp
ব্যাখ্যা
P = FV = \(\frac{100 \times 30}{1000} = 3 kW\)
\(\frac{3}{0.75} = 4hp\)
\(\frac{3}{0.75} = 4hp\)