WAEC - Physics (2010 - No. 11)
simple harmonic oscillator has a period of 0.02s and amplitude of 0.25m. Calculate the speed in ms-1 at the centre of the oscillation
125\(\pi\)
25.00\(\pi\)
100.00 \(\pi\)
400.00\(\pi\)
ব্যাখ্যা
V = WX = \(\frac{2\pi \times 0.25}{0.02} = 25\pi\)