WAEC - Physics (2002 - No. 44)
In a model of the hydrogen atom, the energy levels Wn are given by the formula Wn = -\(\frac{R}{n^2}\), where n is an integer and R is a constant. Determine the energy released in the transition from n = 3 to n = 2.
\(\frac{R}{5}\)
-\(\frac{R}{4}\)
\(\frac{5R}{36}\)
\(\frac{-5R}{36}\)
ব্যাখ্যা
Given that W = -\(\frac{R}{n^2}\)
from n = 3 to n = 2.
-\(\frac{R}{3^2}\) - (-\(\frac{R}{2^2}\))
-\(\frac{R}{9}\) - (-\(\frac{R}{4}\))
-\(\frac{R}{9}\) + \(\frac{R}{4}\);
with LCM 36
\(\frac{-4R + 9R}{36}\)
= \(\frac{5R}{36}\)