WAEC - Mathematics (1995 - No. 15)
Solve the equation 3x\(^2\) + 25x -18 = 0
-3,2
-2,3
-2,9
-9,2/3
2/3, 9.
ব্যাখ্যা
3x\(^2\) + 25x - 18 = 0
3x\(^2\) + 27x - 2x - 18 = 0
3x(x + 9) - 2(x + 9) = 0
(3x - 2)(x + 9) = 0
x = \(\frac{2}{3}\) or x = -9.
3x\(^2\) + 25x - 18 = 0
3x\(^2\) + 27x - 2x - 18 = 0
3x(x + 9) - 2(x + 9) = 0
(3x - 2)(x + 9) = 0
x = \(\frac{2}{3}\) or x = -9.