WAEC - Further Mathematics (2024 - No. 20)
A particle starts from rest accelerates at 4ms\(^{-2}\). Find the distance covered after 4 seconds.
12 m
14 m
18 m
32 m
ব্যাখ্যা
s = ut + \(\frac{1}{2}\)at\(^2\)
u = 0 ms\(^{-1}\), t = 4 secs, a = 4ms\(^{-2}\)
S = 0.5 x 4 x 16 = 32 m