WAEC - Further Mathematics (2019 - No. 23)
Find the constant term in the binomial expansion of (2x\(^2\) + \(\frac{1}{x^2}\))\(^4\)
10
12
24
42
ব্যাখ্যা
6(2x\(^2\))\(^2\) (\(\frac{1}{x^2}\))\(^2\)
= 6 x 2
= 12
6(2x\(^2\))\(^2\) (\(\frac{1}{x^2}\))\(^2\)
= 6 x 2
= 12