WAEC - Further Mathematics (2010 - No. 18)
Find the axis of symmetry of the curve \(y = x^{2} - 4x - 12\).
x = -2
y = -2
x = 2
y = 2
ব্যাখ্যা
The vertical line \(x = \frac{-b}{2a}\) is the axis of symmetry of the curve.
\(y = x^{2} - 4x - 12\)
\(\text{Axis of symmetry} = x = \frac{-(-4)}{2(1)} = \frac{4}{2} = 2\)