WAEC - Further Mathematics (2006 - No. 18)
Simplify \(\frac{^{n}P_{4}}{^{n}C_{4}}\)
24
18
12
6
ব্যাখ্যা
\(^{n}P_{4} = \frac{n!}{(n - 4)!}\)
\(^{n}C_{4} = \frac{n!}{(n - 4)! 4!}\)
\(\frac{^{n}P_{4}}{^{n}C_{4}} = \frac{n!}{(n - 4)!} ÷ \frac{n!}{(n - 4)! 4!}\)
= \(4! = 24\)