JEE Advance - Mathematics (1980 - No. 20)
A straight line $$L$$ is perpendicular to the line $$5x - y = 1.$$ The area of the triangle formed by the line $$L$$ and the coordinate axes is $$5$$. Find the equation of the Line $$L$$.
$$x + 5y - 5\sqrt{2} = 0$$
$$x + 5y + 5\sqrt{2} = 0$$
$$x - 5y - 5\sqrt{2} = 0$$
$$x - 5y + 5\sqrt{2} = 0$$
$$5x + y + 5\sqrt{2} = 0$$