JEE Advance - Chemistry (1985 - No. 18)
Calculate the root mean square velocity of ozone kept in a closes vessel at 20oC and 82 cm mercury pressure.
2.9 x 10^4 cm/sec
3.9 x 10^4 cm/sec
4.9 x 10^4 cm/sec
5.9 x 10^4 cm/sec
6.9 x 10^4 cm/sec
ব্যাখ্যা
$${U_{rms}} = \sqrt {{{3RT} \over M}} = \sqrt {{{3 \times 8.314 \times {{10}^7} \times 293} \over {48}}} $$
$$ = 3.9 \times {10^4}$$ cm sec$$-$$1