JEE Advance - Chemistry (1981 - No. 1)
The energy of the electron in the second and the third Bohr's orbits of the hydrogen atom is -5.42 $$\times$$ 10-12 erg and -2.41 $$\times$$ 10-12 erg respectively. Calculate the wavelength (in Å) of the emitted radiation when the electron drops from the third to second orbit.
6563 Å
6500 Å
6603 Å
6000 Å
7000 Å