JEE MAIN - Physics (2005 - No. 61)
A particle of mass 0.3 kg subjected to a force $$F=-kx$$ with $$k=15$$ $$N/m$$. What will be its initial acceleration if it is released from a point 20 cm away from the origin?
$$15\,\,\,\,m/{s^2}$$
$$3\,\,\,m/{s^2}$$
$$10\,\,\,m/{s^2}$$
$$5\,\,\,m/{s^2}$$
ব্যাখ্যা
Given F = - kx
$$\Rightarrow$$ F = - 15$$ \times {{20} \over {100}}$$ = - 3 N
F = m.a = 3 N
$$\Rightarrow$$ a = $${3 \over m}$$ = $${3 \over {0.3}}$$ = 10 m/s2