(a) $$\,\,\,\,$$

(b) $$\,\,\,\,$$

(c) $$\,\,\,\,$$

(d) $$\,\,\,\,$$

So, option (B) is correct

Note :
If in carbon(C) all 4 bonds are sigma bond then it is sp³ hybridization and if there is 3 sigma bond then sp² and if there is only 2 sigma bond there sp hybridization.