JAMB - Physics (2014 - No. 6)
Calculate the escape velocity of a satellite launched from the earth's surface if the radius of the earth is 6.4x106m
25.3kms-1
4.2kms-1
4.0kms-1
11.3kms-1
ব্যাখ্যা
Vescape = \(\sqrt{2gR}\)
Vescape = \(\sqrt{2\times10\times6.4\times10^6}\)
Vescape = \(\sqrt{128000000}\)
Vescape = 11313.7085mS-1
Vescape = 11.313kmS-1
Vescape = \(\sqrt{2\times10\times6.4\times10^6}\)
Vescape = \(\sqrt{128000000}\)
Vescape = 11313.7085mS-1
Vescape = 11.313kmS-1