JAMB - Physics (1995 - No. 29)
Two parallel plates at a distance of 8.0 x 10-3m apart are maintained at a p.d of 600 volts with the negative plate earthed. What is the electric field strength?
4.8 Vm-1
75.0Vm-1
4800.0Vm-1
75000.0Vm-1
ব্যাখ্যা
E = \(\frac{voltage}{distance}\)
= \(\frac{600}{8 \times 10^2}\)
= 75000.0Vm-1
= \(\frac{600}{8 \times 10^2}\)
= 75000.0Vm-1