JAMB - Physics (1993 - No. 39)
The diagram above shows a velocity time graph representing the motion of a car. Find the total distance covered during the acceleration and retardation of the motion
75m
150m
300m
375m
ব্যাখ্যা
Distance during acceleration
= area of the first triangle = \(\frac{1}{2}\) x 10 x 10 = 50m
Distance during retardation( deceleration)
= area of second triangle = \(\frac{1}{2}\) x 5 x 10 = 25m
Total Distance = 50 + 25 = 75m.