JAMB - Mathematics (2015 - No. 13)

Find the equation of a line which is form origin and passes through the point (−3, −4)

y = \( \frac{3x}{4} \)

y = \( \frac{4x}{3} \)

y = \( \frac{2x}{3} \)

y = \( \frac{x}{2} \)

The slope of the line from (0, 0) passing through (-3, -4) = \(\frac{-4 - 0}{-3 - 0}\)

= \(\frac{4}{3}\)

Equation of a line is given as \(y = mx + b\), where m = slope and b = intercept.

To get the value of b, we use a point on the line, say (0, 0).

\(y = \frac{4}{3} x + b\)

\(0 = \frac{4}{3}(0) + b\)

\(b = 0\)

The equation of the line is \(y = \frac{4}{3} x\)