JAMB - Mathematics (2011 - No. 31)
A man walks 100 m due West from a point X to Y, he then walks 100 m due North to a point Z. Find the bearing of X from Z.
195o
135o
225o
045o
ব্যাখ্যা
tan\(\theta\) = \(\frac{100}{100}\) = 1
\(\theta\) = tan-1(1) = 45o
The bearing of x from z is N45oE or 135o
\(\theta\) = tan-1(1) = 45o
The bearing of x from z is N45oE or 135o