JAMB - Mathematics (2010 - No. 16)
If y = (2x + 1)\(^3\) find \(\frac{\text{d}}{\text{dx}}\)
3(2x+1)2
6(2x+1)
3(2x+1)
6(2x+1)2
ব্যাখ্যা
y = (2x + 1)\(^3\)
\(\frac{dy}{dx}\) = 3(2x + 1)\(^{3-1}\) x 2
= 3(2x + 1)\(^2\)x 2
= 6(2x + 1)\(^2\)
\(\frac{dy}{dx}\) = 3(2x + 1)\(^{3-1}\) x 2
= 3(2x + 1)\(^2\)x 2
= 6(2x + 1)\(^2\)