JAMB - Mathematics (2002 - No. 9)
The slope of the tangent to the curve y = 3x\(^2\) - 2x + 5 at the point (1, 6) is
4
1
6
5
ব্যাখ্যা
y = 3x\(^2\) - 2x + 5
Slope = \(\frac{\mathrm d y}{\mathrm d x} = 6x - 2\)
At x = 1,
Slope : 6(1) - 2 = 4.
y = 3x\(^2\) - 2x + 5
Slope = \(\frac{\mathrm d y}{\mathrm d x} = 6x - 2\)
At x = 1,
Slope : 6(1) - 2 = 4.