JAMB - Mathematics (1998 - No. 27)
If y = 243(4x + 5)-2, find \(\frac{dy}{dx}\) when x = 1
\(\frac{-8}{3}\)
\(\frac{3}{8}\)
\(\frac{9}{8}\)
-\(\frac{8}{9}\)
ব্যাখ্যা
y = 243(4x + 5)-2, find \(\frac{dy}{dx}\)
= -1944(4x + 5)-3
= 1944(9)-3
\(\frac{dy}{dx}\) when x = 1
= -\(\frac{1944}{9^3}\)
= -\(\frac{1944}{729}\)
= \(\frac{-8}{3}\)
= -1944(4x + 5)-3
= 1944(9)-3
\(\frac{dy}{dx}\) when x = 1
= -\(\frac{1944}{9^3}\)
= -\(\frac{1944}{729}\)
= \(\frac{-8}{3}\)