JAMB - Mathematics (1997 - No. 27)
The angle between the positive horizontal axis and a given line is 135o. Find the equation of the line if it passes through the point (2,3)
x - y = 1
x + y = 1
x + y = 5
x - y = 5
ব্যাখ্যা
m = tan 135o = -tan 45o = -1
\(\frac{y - y_1}{x - x_1}\) = m
\(\frac{y - 3}{x - 2}\) = -1
= y - 3 = -(x - 2)
= -x + 2
x + y = 5
\(\frac{y - y_1}{x - x_1}\) = m
\(\frac{y - 3}{x - 2}\) = -1
= y - 3 = -(x - 2)
= -x + 2
x + y = 5