JAMB - Mathematics (1988 - No. 30)
Solve the following equation equation for \(x^2 + \frac{2x}{r^2} + \frac{1}{r^4}\) = 0
r2
\(\frac{1}{r^4}\)
-\(\frac{1}{r^2}\)
1 - r
ব্যাখ্যা
\(x^2 + \frac{2x}{r^2}\) + \(\frac{1}{r^4}\) = 0
(x + \(\frac{1}{r^2}\)) = 0
x + \(\frac{1}{r^2}\) = 0
x = \(\frac{-1}{r^2}\)
(x + \(\frac{1}{r^2}\)) = 0
x + \(\frac{1}{r^2}\) = 0
x = \(\frac{-1}{r^2}\)