JAMB - Mathematics (1985 - No. 40)
If a{\(\frac{x + 1}{x - 2} - \frac{x - 1}{x + 2}\)} = 6x. Find a in its simplest form
x2 - 1
x2 + 1
x2 + 4
x2 - 4
1
ব্যাখ্যা
a{\(\frac{x + 1}{x - 2} - \frac{x - 1}{x + 2}\)} = a{\(\frac{(x + 1)(x + 2)- (x - 1)(x - 2)}{(x - 2)(x + 2)}\)}
= 6
\(\frac{6x}{x^2 - 4}\) = 6x
a = x2 - 4
= 6
\(\frac{6x}{x^2 - 4}\) = 6x
a = x2 - 4